10.24+b^2=25

Solution for 10.24+b^2=25 equation:

10.24+b^2=25

We move all terms to the left:

10.24+b^2-(25)=0

We add all the numbers together, and all the variables

b^2-14.76=0

a = 1; b = 0; c = -14.76;
Δ = b2-4ac
Δ = 02-4·1·(-14.76)
Δ = 59.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{59.04}}{2*1}=\frac{0-\sqrt{59.04}}{2}
=-\frac{\sqrt{}}{2}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{59.04}}{2*1}=\frac{0+\sqrt{59.04}}{2}
=\frac{\sqrt{}}{2}
$